Punnet sqaure help?

in dogs wire hair (S) is dominant to smooth (s) .In a cross of homozygous wire haired dog with a smooth haired dog, what whill be the phenotype of the f1 generation? what would be the genotype?

if u can explain that would be nice cause i really dont get punnet sqaures and i would like to actually learn how so i can do the rest of my homework! thanks

Punnet sqaure help?

wrong section?

isn't this biology?

Punnet sqaure help?

this question is for science, not math, so you might get better answers if you post this in there

Punnet sqaure help?

Im learning about punnett squares right now

I think that the F1 generation would be dominant (S)

The penotype would be dominant and the genotype would be recessive

hope that helps

Punnet sqaure help?

This is more of a biology question than a mathematics quesiton, but...

These sites do a good job as explaining Punnett square construction:

http://anthro.palomar.edu/mendel/mendel_...

http://en.wikipedia.org/wiki/Punnett_squ...

In this case you're going to cross "SS" with "ss".

Punnet sqaure help?

homozygous-means same allelle (same gene). So-homozygous wire means both genes are SS. and if the other dog is smooth(the recessive gene) then it's allelle pair is ss. When you cross SS with ss the dominant S will always show over the recessive s. So all four f1 generation dogs will have genotype Ss, and phenotype Wire Hair. Sorry- i can't explain it any better without drawing the punnett square. Good Luck on your homework!

Punnet sqaure help?

homozygous means SS

Smooth haired dog is: ss

so here is how you set it up:

........ S ........ S

s ... Ss ....... Ss

s ... Ss ....... Ss

Phenotype is what is expressed:

Genotype is genetic make-up

so for the fist F1

phenotype: 4 wired hair dogs

genotype: 4 heterozygous wire haird dog

Punnet sqaure help?

The parental generation will be SS and ss. Here's why: for the dog to be wire hair, it needs to have either an SS or Ss because wire hair is dominant. For it to be a smooth hair, it needs to be ss because smooth hair is recessive. So you know for sure that one is ss. Now for the wire hair one, it told you it's homozygous (meaning same alleles), so you now know it's SS. If it had been heterozygous, it would've been Ss.

When you cross SS dog and ss dog, the F1 generation (offspring of parental generation) will be 100% Ss for their genotype and 100% wire haired.

You make a 4-squared punnet square by dividing a big square into 4 squares. You put SS at the top and ss on the side. You then just put them together for each square making them each Ss. They will all be wire haired because they're all heterozygous for it, meaning a dominant allele for wired haired and a recessive for smooth. The dominant will be showed and the recessive will not, making the trait outcome being wire haired.

Lets say the parental generation was Ss and SS. So make the square and put it together for each square. You'd end up with 50% SS, 50% Ss. !00% wire haired.

I hope this all makes sense. I'm not exactly a teacher, but we just covered this unit and I happen to have an extremely good Bio. teacher. Good luck.